[profile] guinevere33 and math people, i need help.

16 Nov 2004 04:16 pm
cimorene: cartoony drawing of a woman's head in profile giving dubious side-eye (Default)
[personal profile] cimorene
gather round for the value-added actor formula.

(16:04:04) waxismo:  If the film in question is X, and your eagerness to see it is Y, and X = Y, then (X + Steve Buscemi) = 2Y. Or something like that.
(16:08:04) cimmajesty: what you want is like, Y(x in its base state)=X+(sum of values of value-added actors)
(16:08:40) cimmajesty: or in some cases, X(to the value of value added-actor power)
(16:10:03) cimmajesty: only, no, it can't be exponential because if a movie was a negative two and liev was to-the-tenth-power, then movie x with liev would be negative two to the tenth.


so how would you resolve this?


(16:01:14) waxismo: Most everyone has a personal stable of favourite actors. Not poster-on-the-wall, secret-crush, my-hero-type favourites, but supporting actors who have some appealing quality, and as such could be described, in salesmen's lingo, as "value-added."
(16:01:43) cimmajesty: value-added? what does that mean?  that means that they have appealing qualities?
(16:02:07) waxismo: it means that this one quality of it will increase the value of the product.
(16:02:31) waxismo: or that this component will always increase the value of the final product, I guess.
(16:02:53) waxismo: youhave a movie with your average movie stars. add one value-added supporting actor and... value is added!
(16:03:02) waxismo: Liev used to be one of my value-added actors.
(16:03:15) waxismo: he's been upgraded to poster-on-the-wall status, though.
(16:04:04) waxismo:  If the film in question is X, and your eagerness to see it is Y, and X = Y, then (X + Steve Buscemi) = 2Y. Or something like that.
(16:04:06) waxismo: ahahah.
(16:04:23) waxismo: steve buscemi is on my list too.
(16:04:33) cimmajesty: yes, i get it now.
(16:04:59) cimmajesty: only 2Y is wrong
(16:05:34) waxismo: Liev's Y factor has been increased exponentially, however, so now I'm likely to see even a movie with a negative Y score because he's in it. so the formula has to change a little to give him the special power of turning minus to plus.
(16:06:08) cimmajesty: no, see, the way you made the formula, y is always the amount you want to see it
(16:06:13) cimmajesty: no matter who's in it.
(16:06:29) cimmajesty: it's just that y(movie with steve buscemi) is greater than y(movie without steve buscemi)
(16:07:43) waxismo: I didn't make the formula
(16:08:04) cimmajesty: what you want is like, Y(x in its base state)=X+(sum of values of value-added actors)
(16:08:40) cimmajesty: or in some cases, X(to the value of value added-actor power)
(16:10:03) cimmajesty: only, no, it can't be exponential because if a movie was a negative two and liev was to-the-tenth-power, then movie x with liev would be negative two to the tenth.
(16:10:29) waxismo: I mentioned that he had special powers.
(16:10:31) cimmajesty: liev perhaps just has a very high value.
(16:10:47) cimmajesty: like, when you have your current crush on an actor, he's a 210 instead of a 10.
(16:11:10) cimmajesty: thus, if the movie's base score was, say, -50, with liev it'd still be 160.

(no subject)

Date: 16 Nov 2004 02:21 pm (UTC)
From: [identity profile] ex-thewayout304.livejournal.com
I'm more than a little amused by the fact that you guys live together, and yet you still talk about these things over IM.

(no subject)

Date: 16 Nov 2004 02:29 pm (UTC)
From: [identity profile] ex-thewayout304.livejournal.com
Also, I think it should be Y(X) = X + {[X]^(VAAP1+VAAP2+...)-1}.

Which can be read as, "Y as a function of X is equal to X plus the absolute value of X to the sum of the power of value-added actor(s) minus one." That way if X is a negative number, it can be overcome by the second factor because it is an absolute value, which is always positive. And if there aren't any VVAPs, then that factor becomes simply 1, but you subtract 1 anyway so then Y=X.

(no subject)

Date: 16 Nov 2004 02:37 pm (UTC)
From: [identity profile] wax-jism.livejournal.com
the power of the sum of actors, right?

but this does work. excellent! now just to create a list of VAAPs and give them points. and also a scale of Y. etc. so much work, so little time.

(no subject)

Date: 16 Nov 2004 02:51 pm (UTC)
From: [identity profile] ex-thewayout304.livejournal.com
Yep. It is really hard to express the order of operations on here because I dont have enough little bracket thingies. But that second part should be [(absolute value of X) to the power of the sum of actors] minus 1.

(no subject)

Date: 16 Nov 2004 02:51 pm (UTC)
From: [identity profile] cimness.livejournal.com
i think if X=-2 and there were no VAAPs, X^0=1, because anything to the zero power is one.

whereas elaine's formula yields Y=-2+((2^0)-1)=-2+1-1.

(no subject)

Date: 16 Nov 2004 02:40 pm (UTC)
From: [identity profile] cimness.livejournal.com
oooh awesome.

yeah, that was the main reason wax wanted to put the computers in other rooms. 'so we can be geeky and im each other!' she said excitedly.

(no subject)

Date: 16 Nov 2004 02:34 pm (UTC)
From: [identity profile] fmith.livejournal.com
If I was good at math, I would use this formula.

(no subject)

Date: 16 Nov 2004 04:30 pm (UTC)
From: [identity profile] brc.livejournal.com
Re: cards... You celebrate Hanukkah, not Christmas, right?

(no subject)

Date: 16 Nov 2004 07:41 pm (UTC)
From: [identity profile] cimness.livejournal.com
i'm a flexible atheist. i grew up with both. :)

(no subject)

Date: 16 Nov 2004 07:42 pm (UTC)
From: [identity profile] cimness.livejournal.com
:gah they are socute:

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